10x^2+23x-9=4

Solution for 10x^2+23x-9=4 equation:

10x^2+23x-9=4

We move all terms to the left:

10x^2+23x-9-(4)=0

We add all the numbers together, and all the variables

10x^2+23x-13=0

a = 10; b = 23; c = -13;
Δ = b2-4ac
Δ = 232-4·10·(-13)
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1049}}{2*10}=\frac{-23-\sqrt{1049}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1049}}{2*10}=\frac{-23+\sqrt{1049}}{20}
$